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我的是K+n^2*lg(n)*lg(n)，你是怎么搞的？是不是2D RMQ有点不适用这题。。In Reply To:K*B^2的暴力确实可以过，我优化到了K + n^2 * logB，最优是什么复杂度啊，欢迎回信讨论 Posted by:blablabla at 2007-06-23 00:30:29 rt.. Followed by: Post your reply here: |
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