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注意有重边,你好像没有考虑!!In Reply To:我为啥用Prim不能AC Posted by:030501619 at 2007-06-01 12:33:40 > 如题,总说WA。 > 牛人帮我看下把 > #include<iostream> > using namespace std; > int main() > { > int n,m; > while(cin>>n>>m) > { > int i,j,k=0,u,v; > long l,max,min; > long **a=new long *[m]; > for(i=0;i<m;i++) > a[i]=new long [3]; > long **b=new long *[n+1]; > for(i=0;i<n+1;i++) > b[i]=new long [n+1]; > for(i=1;i<n+1;i++) > for(j=1;j<n+1;j++) > b[i][j]=0; > for(i=0;i<m;i++) > { > cin>>u>>v>>l; > b[u][v]=b[v][u]=l; > } > for(i=1;i<n+1;i++) > for(j=1;j<n+1;j++) > if(b[i][j]==0) > b[i][j]=2147483647; > bool *s=new bool [n+1]; > long *lowcost=new long [n+1]; > int *closest=new int [n+1]; > s[1]=true; > for(i=2;i<=n;i++){ > lowcost[i]=b[1][i]; > closest[i]=1; > s[i]=false; > } > for(i=1;i<n;i++){ > min=2147483647; > j=1; > for(k=2;k<=n;k++) > if((lowcost[k]<min)&&(!s[k])){ > min=lowcost[k]; > j=k; > } > s[j]=true; > for(k=2;k<=n;k++) > if((b[j][k]<lowcost[k])&&(!s[k])){ > lowcost[k]=b[j][k]; > closest[k]=j; > } > } > max=0; > for(i=2;i<=n;i++) > if(s[i]==true&&lowcost[i]>max) > max=lowcost[i]; > cout<<max<<endl; > } > return 0; > } Followed by:
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