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Re:看一下哦In Reply To:看一下哦 Posted by:uestczhangchao at 2007-05-23 10:52:36 > > #include<iostream> > using namespace std; > #include<math.h> > int main(){ > int i,j,n,sum; int sum1=0;int k=0; > int a[50],b[50]; > for(;;) > { > cin>>n; > if(n==0) break; > sum=0; > for(i=1;i<n;i++) > { > sum=sum+i*i; > if(n==(i*i+i)/2) > sum1=sum; > > else if(n>(i*i-i)/2&&n<=(i*i+i)/2) > sum1=sum-((i*i+i)/2-n)*i; > > } > a[k]=n; > b[k]=sum1; > k++; > } > for(j=0;j<k;j++) > {cout<<a[j]<<" "<<b[j]<<endl;} > > return 0; > } > > Followed by: Post your reply here: |
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