 |
| ||||
Home Page
F.A.Qs
Statistical Charts
Past Contests
Scheduled Contests
Award Contest
| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
我用了字符串的方法,有更高效的方法吗??#include <iostream.h>
#include <stdlib.h>
#include <string.h>
void main()
{
long i,j,k,m,n,sum;
char a[10];
int radix=10;
cin>>m;
for(i=0;i<m;i++)
{
cin>>n;
k=1; sum=1;
while (n>sum)
{
n=n-sum;
k++;
ltoa(k,a,radix);
sum=sum+strlen(a);
}
j=1; sum=1;
ltoa(j,a,radix);
while (n>sum)
{
n=n-sum;
j++;
ltoa(j,a,radix);
sum=strlen(a);
}
n--;
cout<<a[n]<<endl;
}
}
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator
