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dp[i][j]=dp[i][j-1]+dp[i-1][j/2] O(N^2) 不是更简单啊？In Reply To:用DP。 dp[i][j]表示从前j个数中选出i个满足条件的组合数 Posted by:wrong123 at 2005-12-12 00:38:04 Followed by: Post your reply here: |
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