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aaa

Posted by zhuang000 at 2007-05-11 19:06:01 on Problem 1517

#include "stdio.h"
int main()
{ int n;
  double e=0;
  double sum=1;
  printf("n e\n- -----------\n");
  for(n=0;n<=9;n++){
      if(n!=0)sum=n*sum;
      e+=1/sum;
      printf("%d %.9lf\n",n,e);
  }
  return 0;
}

Followed by:

Re:aaa (260) neverend 2007-08-05 17:29:46
Re:aaa (260) neverend 2007-08-05 17:30:01
Re:aaa (6) neverend 2007-08-05 17:30:12

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