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Re:连立(1,2,3),可以求出abc,自然就得到了多项式,然后想求什么不就很简单了?不要误导别人噢.!!In Reply To:Re:连立(1,2,3),可以求出abc,自然就得到了多项式,然后想求什么不就很简单了?不要误导别人噢.!! Posted by:wsbear at 2006-07-30 04:33:18 我的另一个思路： 二次函数的差分是一次函数，即将f（0），f（1）。。。f（5）作差，所得差是等差数列。以此可得结果。 Followed by: Post your reply here: |
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