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Re:"只有完全平方数有奇数个相异因数",谁能证明一下?In Reply To:"只有完全平方数有奇数个相异因数",谁能证明一下? Posted by:zyz at 2007-04-25 21:07:58 因子 m 和 n/m 可以两两配对。。 所以奇数个因子的数必有某个m使m=n/m ===> n=m^2 强烈建议问这类问题之前去wiki或者mathworld之类的地方查下。。 > 为什么非完全平方数不能有奇数个相异因数? Followed by:
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