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Re:Floyd不超才怪

Posted by a024014 at 2007-04-18 18:33:07 on Problem 2570
In Reply To:Floyd不超才怪 Posted by:T3 at 2005-08-15 17:50:12

for(k=1;k<=n;k++)
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
	a[i][j]|=a[i][k]&a[k][j];
floyd不会超吧.我的78ms,还有别的方法吗?

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