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先按X排序算一次,再按Y排序算一次.. over!

Posted by Sempr at 2007-04-09 16:10:55 on Problem 3212
In Reply To:Re:怎么才不超时呀??? Posted by:YUMEN19850720 at 2007-04-09 15:59:38
> (x.y)->((x+y)/2,(x-y)/2)
> 
> 转换成hamilton距离

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