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为什么会RE??In Reply To:为什么会 Posted by:butter at 2007-04-04 20:18:04 find2()那个函数莫名其妙的Runtime Error,是不是数据有问题啊 #include <cstdio> #define MAXN 1101 struct node { int f,m; int sex; int deep1,deep2; }vert[MAXN]; int temp[MAXN]; void find1(int i) { if(vert[i].f==i&&vert[i].m==i) return; vert[vert[i].f].deep1=vert[i].deep1+1; vert[vert[i].m].deep1=vert[i].deep1+1; find1(vert[i].f); find1(vert[i].m); } void find2(int i) { if(vert[i].f==i&&vert[i].m==i) return; vert[vert[i].f].deep2=vert[i].deep2+1; vert[vert[i].m].deep2=vert[i].deep2+1; find2(vert[i].f); find2(vert[i].m); } int main() { int p1,p2,i,j,v,t; scanf("%i%i",&p1,&p2); for(i=1;i<=MAXN-1;i++) { vert[i].f=vert[i].m=i; vert[i].deep1=vert[i].deep2=10; vert[i].sex=0; } while(scanf("%i\n",&v)!=EOF) { temp[0]=0; while(1) { scanf("%i",&temp[++temp[0]]); if(temp[temp[0]]<=0) { vert[v].sex=temp[temp[0]]; break; } } if(vert[v].sex==0) for(i=1;i<temp[0];i++) vert[temp[i]].f=v; else for(i=1;i<temp[0];i++) vert[temp[i]].m=v; } if(vert[p1].sex==vert[p2].sex) { printf("same\n"); return 0; } else { vert[p1].deep1=0; find1(p1); vert[p2].deep2=0; find2(p2);//就是这个函数会RE,不知道为什么 for(i=1;i<MAXN;i++) if((vert[i].deep1<=3)&&(vert[i].deep2<=3)) { printf("close\n"); goto label; } printf("marriage\n"); } label: return 0; } Followed by:
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