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其他OJ过了啊 PKU不过 过了的朋友看看~#include <stdio.h>
#include <algorithm>
using namespace std;
const int MAXINT = 2000000000;
const int N = 1005;
struct Node {int a, b, c;}A[N*N], B[N*N];
int n;
int x[N];
bool operator<(const Node& a, const Node& b) {
return a.c < b.c;
}
int main() {
int i, j;
while(scanf("%d", &n), n) {
if(n < 4) {
printf("no solution\n");
continue;
}
for(i = 0; i < n; i++)
scanf("%d", x+i);
int k = 0;
for(i = 0; i < n; i++) {
for(j = i+1; j < n; j++) {
if(x[i] != x[j]) {
A[k].c = x[i] + x[j];
A[k].a = x[i];
A[k].b = x[j];
k++;
}
}
}
int k2 = 0;
for(i = 0; i < n; i++) {
for(j = 0; j<n; j++) {
if(x[i] != x[j]) {
B[k2].c = x[i] - x[j];
B[k2].a = x[i];
B[k2].b = x[j];
k2++;
}
}
}
sort(A, A+k);
sort(B, B+k2);
i = k-1, j = k2-1;
int _max = -MAXINT;
while(i >= 0 && j >= 0) {
if(A[i].c != B[j].c) {
if(A[i].c > B[j].c) i--;
else j--;
continue;
}
int o = j;
while(A[i].c == B[j].c && j >= 0) {
if(A[i].a != B[j].a && A[i].a != B[j].b && A[i].b != B[j].a && A[i].b != B[j].b) {
if(B[j].a > _max) _max = B[j].a;
}
j--;
}
i--;
j = o;
}
if(_max == -MAXINT) printf("no solution\n");
else printf("%d\n", _max);
}
return 0;
}
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