//我的solution
#include <iostream>
#include <string>

using namespace std;

int main()
{
	string input;
	char array[26]={'V','W','X','Y','Z','A','B','C','D','E','F',
					'G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U'};
	unsigned int i;
	int index;
	while(1)
	{
		getline(cin,input);
		if(input=="ENDOFINPUT")//end of input
			break;
		else if(input=="START"||input=="END")//the start and end
				continue;
		else
			for(i=0;i<input.size();i++)
				if(input[i]>='A'&&input[i]<='Z')
				{
					index=input[i]-'A';
					input[i]=array[index];//xlat查表
				}
		cout<<input<<endl;
	}
	return 0;
}

• Re:C++ (用cin.ignore解决疑难问题） (700) lynxpengpeng 2007-09-30 15:15:58
  • Re:C++ (用cin.ignore解决疑难问题） (4) lynxpengpeng 2007-09-30 15:17:03
  • Re:C++ (用cin.ignore解决疑难问题） (5) smileallthetime 2008-12-21 15:47:00