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换别的排序方法试试In Reply To:请问怎么才能让这个程序时间再缩短阿????!!!!!已经用了快速排序,还是TLE!!!谢谢了 Posted by:1234_ at 2007-03-17 20:31:06 > #include<iostream.h>
> #include <stdlib.h>
> #include<cstring>
> struct state
> {
> char digit[15];
> int num;
> };
> int main()
> {
> void change(char *a);
> int mycompare(const void *elem1,const void *elem2);
> int n;
> cin>>n;
> cin.ignore();
> state *number=new state[n];
> int i,j,count=0;
> char tmp[20];
> for(i=0;i<n;i++)
> {
> number[i].digit[0]='\0';
> number[i].num=0;
> }
> for(i=0;i<n;i++)
> {
> cin.getline(tmp,20);
> change(tmp);
> for(j=0;j<count;j++)
> {
> if(strcmp(tmp,number[j].digit)==0)
> {
> number[j].num++;
> break;
> }
> }
> if(j==count)
> {
> strcpy(number[count].digit,tmp);
> number[count].num++;
> count++;
> }
> }
> qsort(number,n,sizeof(state),mycompare);
> for(i=0;i<n;i++)
> {
> if(number[i].num>1)
> {
> cout<<number[i].digit<<' '<<number[i].num<<endl;
> }
> }
> delete []number;
> return 0;
> }
> void change(char *a)
> {
> int i,j=0;
> char tmp[9];
> for(i=0;i<strlen(a);i++)
> {
> if(a[i]>='0'&&a[i]<='9')
> {
> tmp[j]=a[i];
> j++;
> }
> else if(a[i]>='A'&&a[i]<='C')
> {
> tmp[j]='2';
> j++;
> }
> else if(a[i]>='D'&&a[i]<='F')
> {
> tmp[j]='3';
> j++;
> }
> else if(a[i]>='G'&&a[i]<='I')
> {
> tmp[j]='4';
> j++;
> }
> else if(a[i]>='J'&&a[i]<='L')
> {
> tmp[j]='5';
> j++;
> }
> else if(a[i]>='M'&&a[i]<='O')
> {
> tmp[j]='6';
> j++;
> }
> else if(a[i]>='P'&&a[i]<='S'&&a[i]!='Q')
> {
> tmp[j]='7';
> j++;
> }
> else if(a[i]>='T'&&a[i]<='V')
> {
> tmp[j]='8';
> j++;
> }
> else if(a[i]>='W'&&a[i]<='Y')
> {
> tmp[j]='9';
> j++;
> }
> }
> tmp[7]=tmp[6];
> tmp[6]=tmp[5];
> tmp[5]=tmp[4];
> tmp[4]=tmp[3];
> tmp[3]='-';
> tmp[8]='\0';
> strcpy(a,tmp);
> }
> int mycompare(const void *elem1,const void *elem2)
> {
> state *p1,*p2;
> p1=(state *)elem1;
> p2=(state *)elem2;
> return (strcmp(p1->digit,p2->digit));
> }
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