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Re:han3(1)=1;

Posted by mayp at 2007-03-12 15:50:22 on Problem 1958
In Reply To:给出一个公式吧..自己也可以推推 Posted by:mayp at 2007-03-12 15:49:48

> han4(1)=1;
> han4(n)=min(2*han4(i)+han3(n-i))   (0<i<n)
> han3(n)=2*han3(n-1)+1;
> han3,han4表示有3,4个POLE,同样的思路,可以将其推广到任意POLE,当然,复杂度也会很高..

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