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给出一个公式吧..自己也可以推推han4(1)=1; han4(n)=min(2*han4(i)+han3(n-i)) (0<i<n) han3(n)=2*han3(n-1)+1; han3,han4表示有3,4个POLE,同样的思路,可以将其推广到任意POLE,当然,复杂度也会很高.. Followed by:
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