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最傻瓜的思路~~可是..还是wa.,...#include<iostream.h>
#include<string.h>
int main(){
char szLeft[3][12],szRight[3][12],szResult[3][7];
char cNow;
int n,i,j;
cin>>n;
for( i = 0; i < n; i++){
for( j = 0; j < 3 ;j++){
cin>>szLeft[j]>>szRight[j]>>szResult[j];
}
for(cNow = 'A'; cNow <= 'L'; cNow++){
for( j = 0; j < 3 ;j++){
if(szResult[j][0] == 'u' && !strchr(szLeft[j],cNow)) break;
if(szResult[j][0] == 'd' && !strchr(szRight[j],cNow)) break;
if(szResult[j][0] == 'e'
&& (strchr(szLeft[j],cNow) ||strchr(szRight[j],cNow))) break;
}
if(j == 3){
cout<<cNow<<" is the counterfeit coin and it is heavy."<<endl;
return 0;
}
for( j = 0; j < 3 ;j++){
if(szResult[j][0] == 'd' && !strchr(szLeft[j],cNow)) break;
if(szResult[j][0] == 'u' && !strchr(szRight[j],cNow)) break;
if(szResult[j][0] == 'e'
&& (strchr(szLeft[j],cNow) ||strchr(szRight[j],cNow))) break;
}
if(j == 3){
cout<<cNow<<" is the counterfeit coin and it is light."<<endl;
break;
}
}
}
return 0;
}
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