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给个公式 可能有用 0MS算法1步 1值 1*1 2步 2值 3步 4值 2*2 4步 6值 5步 9值 3*3 .. .. n 是步子 ((n+1)/2)的平方就是值或者是在中间的值 i=(int)sqrt(value); a=i*i; b=(i+1)*(i+1); 然后a b再与value做比较就出来了(不用循环直接出来) 下面是几组数据 希望有帮助 8 59 4512 输出133 45 654 输出49 4 1545 输出78 .. .. ... Followed by:
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