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啊 忘记不要涂鸦了 不好意思啊。。。In Reply To:枚举的思路 Posted by:oyjpart at 2007-02-16 15:03:58 > #include <stdio.h> > int main() { > int ntc, i, j, k, d[3], l; > char a[3][7], b[3][7], tmp[5]; > scanf("%d", &ntc); > while(ntc--) { > for(i = 0; i<3; i++) { > scanf("%s %s %s", a[i], b[i], tmp); > if(tmp[0] == 'd') d[i] = -1; > else d[i] = tmp[0] == 'u'; > } > for(i = 0; i<12; i++) > for(l = -1; l<=1; l+= 2) { > for(j = 0; j<3; j++) { > int wa = 0, wb = 0; > for(k = 0; a[j][k]; k++) wa += (a[j][k]-'A'==i)*l; > for(k = 0; b[j][k]; k++) wb += (b[j][k]-'A'==i)*l; > if(wa - wb != d[j]) break; > } > if(j != 3) continue; > printf("%c is the counterfeit coin and it is ", (char)(i+'A')); > if(l == 1) printf("heavy.\n"); > else printf("light.\n"); > } > } > return 0; > } Followed by: Post your reply here: |
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