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你可以把这个过程看作DP :)In Reply To:这题需要DP么?我直接对所有点排序 然后从小到大计算longest path不行么(记录已经计算的格子的longest path)? 我觉得 Posted by:alpc12 at 2007-02-13 15:50:54 > #include <stdio.h>
> #include <algorithm>
> using std::sort;
> const int N = 101;
> int lgst[N][N];
> struct node{int x, y, h; void set(int xx, int yy, int hh) {x = xx; y=yy; h=hh;}}nd[N*N];
> int brd[N][N];
> int r, c;
>
> bool operator<(const node& a, const node& b) {
> return a.h < b.h;
> }
>
> int main() {
> int i, j;
> scanf("%d%d", &r, &c);
> for(i = 0; i<r; i++)
> for(j = 0; j<c; j++) {
> scanf("%d", &(brd[i][j]));
> nd[i*c+j].set(i, j, brd[i][j]);
> }
> sort(nd, nd+r*c);
> for(i = 0; i < r; i++)
> for(j = 0; j < c; j++)
> lgst[i][j] = 1;
> int max = 1;
> for(i = 1; i<r*c; i++) {
> int x = nd[i].x;
> int y = nd[i].y;
> int h = nd[i].h;
> if(x > 0 && brd[x-1][y] < h)
> if(lgst[x-1][y] + 1 > lgst[x][y])
> lgst[x][y] = lgst[x-1][y] + 1;
> if(x < c-1 && brd[x+1][y] < h)
> if(lgst[x][y] < lgst[x+1][y] + 1)
> lgst[x][y] = lgst[x+1][y] + 1;
> if(y > 0 && brd[x][y-1] < h)
> if(lgst[x][y-1] + 1 > lgst[x][y])
> lgst[x][y] = lgst[x][y-1] + 1;
> if(y < r-1 && brd[x][y+1] < h)
> if(lgst[x][y] < lgst[x][y+1] +1)
> lgst[x][y] = lgst[x][y+1] + 1;
> if(lgst[x][y] > max) max = lgst[x][y];
> }
> printf("%d\n", max);
> return 0;
> }
>
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