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这题需要DP么?我直接对所有点排序 然后从小到大计算longest path不行么(记录已经计算的格子的longest path)? 我觉得#include <stdio.h> #include <algorithm> using std::sort; const int N = 101; int lgst[N][N]; struct node{int x, y, h; void set(int xx, int yy, int hh) {x = xx; y=yy; h=hh;}}nd[N*N]; int brd[N][N]; int r, c; bool operator<(const node& a, const node& b) { return a.h < b.h; } int main() { int i, j; scanf("%d%d", &r, &c); for(i = 0; i<r; i++) for(j = 0; j<c; j++) { scanf("%d", &(brd[i][j])); nd[i*c+j].set(i, j, brd[i][j]); } sort(nd, nd+r*c); for(i = 0; i < r; i++) for(j = 0; j < c; j++) lgst[i][j] = 1; int max = 1; for(i = 1; i<r*c; i++) { int x = nd[i].x; int y = nd[i].y; int h = nd[i].h; if(x > 0 && brd[x-1][y] < h) if(lgst[x-1][y] + 1 > lgst[x][y]) lgst[x][y] = lgst[x-1][y] + 1; if(x < c-1 && brd[x+1][y] < h) if(lgst[x][y] < lgst[x+1][y] + 1) lgst[x][y] = lgst[x+1][y] + 1; if(y > 0 && brd[x][y-1] < h) if(lgst[x][y-1] + 1 > lgst[x][y]) lgst[x][y] = lgst[x][y-1] + 1; if(y < r-1 && brd[x][y+1] < h) if(lgst[x][y] < lgst[x][y+1] +1) lgst[x][y] = lgst[x][y+1] + 1; if(lgst[x][y] > max) max = lgst[x][y]; } printf("%d\n", max); return 0; } Followed by:
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