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这题需要DP么?我直接对所有点排序 然后从小到大计算longest path不行么(记录已经计算的格子的longest path)? 我觉得#include <stdio.h>
#include <algorithm>
using std::sort;
const int N = 101;
int lgst[N][N];
struct node{int x, y, h; void set(int xx, int yy, int hh) {x = xx; y=yy; h=hh;}}nd[N*N];
int brd[N][N];
int r, c;
bool operator<(const node& a, const node& b) {
return a.h < b.h;
}
int main() {
int i, j;
scanf("%d%d", &r, &c);
for(i = 0; i<r; i++)
for(j = 0; j<c; j++) {
scanf("%d", &(brd[i][j]));
nd[i*c+j].set(i, j, brd[i][j]);
}
sort(nd, nd+r*c);
for(i = 0; i < r; i++)
for(j = 0; j < c; j++)
lgst[i][j] = 1;
int max = 1;
for(i = 1; i<r*c; i++) {
int x = nd[i].x;
int y = nd[i].y;
int h = nd[i].h;
if(x > 0 && brd[x-1][y] < h)
if(lgst[x-1][y] + 1 > lgst[x][y])
lgst[x][y] = lgst[x-1][y] + 1;
if(x < c-1 && brd[x+1][y] < h)
if(lgst[x][y] < lgst[x+1][y] + 1)
lgst[x][y] = lgst[x+1][y] + 1;
if(y > 0 && brd[x][y-1] < h)
if(lgst[x][y-1] + 1 > lgst[x][y])
lgst[x][y] = lgst[x][y-1] + 1;
if(y < r-1 && brd[x][y+1] < h)
if(lgst[x][y] < lgst[x][y+1] +1)
lgst[x][y] = lgst[x][y+1] + 1;
if(lgst[x][y] > max) max = lgst[x][y];
}
printf("%d\n", max);
return 0;
}
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