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噢……我是判断每个a[i][i]+a[j][j]?=a[i][j]+a[j][i]的，不过原理也差不多。In Reply To:只判断每个2*2的子矩阵是否满足就行了吧。。。 Posted by:lxp_rs at 2006-08-06 17:43:41 Followed by: Post your reply here: |
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