太谢谢了！
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main(void)
{
	int n[20000],d[20000];
	int mid[20000],r[20000],result[20000];
	int total=1;
	int count,l;
	int i,j,k,p,ltemp,temp;
	scanf("%d %d",&n[total],&d[total]);
	while (!(n[total]==0 && d[total]==0) )
	{
		if (d[total]==0 || n[total]==0) {
			printf("1\n");
			p++;
			total++;
			scanf("%d %d",&n[total],&d[total]);
			continue;
		}
		i=1;
		k=1;
		while ((n[total]/k)>=1) {
			k*=10;
			i++;
		}
		i--;
		l=i;
		k/=10;
		mid[0]=0;
		r[0]=0;
		for (i=1;i<=l;i++) {
			r[i]=n[total]/k;
			n[total]-=r[i]*k;
			k=k/10;
		}
		for (i=1;i<=l/2;i++) {
			temp=r[i];
			r[i]=r[l-i+1];
			r[l-i+1]=temp;
		}  
		for (i=1;i<=l;i++) mid[i]=r[i];
		if (l==1) {
			for (i=1;i<=l;i++) result[i]=r[i];
			ltemp=l;
		}
		ltemp=l;
		for (i=2;i<=d[total];i++)
		{
			for (j=1;j<=l*(d[total]+1);j++) result[j]=0;
			for (j=1;j<=ltemp;j++)
				for (k=1;k<=l;k++)
				{
					result[j+k-1]+=mid[j]*r[k];
					while (result[j+k-1]>9) {
						result[j+k]+=result[j+k-1]/10;
						result[j+k-1]%=10;
					}
				}
			if (result[ltemp+l]!=0) ltemp=ltemp+l;
			else ltemp=ltemp+l;
			for (j=1;j<=ltemp;j++)
				mid[j]=result[j];
		}
		for (i=ltemp;i>=1;i--) if (result[i]!=0) break;
		for (;i>=1;i--) printf("%d",result[i]);
		printf("\n");
		total++;
		scanf("%d %d",&n[total],&d[total]);
		
	}
	return 0;
}

• 大家帮帮忙吧，实在想不出来了。 (15) testdirk 2007-02-08 18:01:55
  • 我是用高精度才过的,你用了没? (19) Iamjw 2007-02-08 18:35:50
    • 用了阿。但是还是一直WA，可能有些特殊情况吧？你能看见我的源程序么？在最上面。 (39) testdirk 2007-02-08 19:00:03
      • 你10 1的答案错了 (54) Iamjw 2007-02-08 22:39:05
        • Re:你10 1的答案错了 (23) testdirk 2007-02-08 23:52:55
          • Re:你10 1的答案错了 (17) Iamjw 2007-02-09 00:21:20