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Re:原来sort+greedy就可以ac - -#In Reply To:原来sort+greedy就可以ac - -# Posted by:LuoYuLong at 2006-06-24 08:04:14 问一下:我的贪心是O(n)+快排
为什么超时?
Problem Id:2376 User Id:wpc0000
Memory:368K Time:1014MS
Language:G++ Result:Time Limit Exceed
Source
//pku2376
#include <stdio.h>
#include <iostream>
//#include <fstream0>
//ifstream cin("in.txt");
//ofstream cout("out.txt");
using namespace std;
const int N0=25000;
int n,t;
int tot;
struct PII{
long b,e;
}node[N0];
bool comp(PII a0,PII b0)
{
if(a0.b<b0.b)return true;
else if(a0.b>b0.b)return false;
else return (a0.e>b0.e);
}
int QuickSort(long l,long r)
{
long i, j, x;
i=l;j=r;x=(l+r)/ 2;
do{
while (comp(node[i],node[x])) i++;
while (comp(node[x],node[j])) j--;
if (i <= j){
PII temp;
temp=node[i];node[i]=node[j];node[j]=temp;
i++; j--;
}
}while( i<=j);
if (l < j) QuickSort(l,j);
if (i < r) QuickSort(i, r);
return 0;
}
int init()
{
for(int i=0;i<n;i++){
scanf("%ld %ld\n",&node[i].b,&node[i].e);
}
tot=0;
QuickSort(0,n-1);
return 0;
}
int turn()
{
int i,j,i0;
tot++;
j=0;
long e=node[j].e;
i=0;
while(j<n){
i0=j;//i=i0;
while( (node[i].b<=node[j].e+1)&&(i<n) ){
if(node[i].e>node[i0].e)i0=i;
i++;
}
if(j!=i0)tot++;
j=i0;
e=node[j].e;
if( (e>=t)||(i>=n) )break;
}
if( (e>=t)&&(node[0].b==1) )cout<<tot<<endl;
else cout<<-1<<endl;
return 0;
}
int main()
{
while(scanf("%d %ld",&n,&t)!=EOF){
init();
turn();
}
return 0;
}
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