> #include <iostream.h>
> #include<iomanip.h>
> 
> 
> int main()
> {
> 	char week[7][10]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};
> 	long fh[26],hh[6],y[6]={0,366,731,1096,1461,1468},days;
> 	int dleap[15]={0,31,60,91,121,152,183,213,244,274,305,335,366,377};
> 	int dfl[15]={0,31,59,90,120,151,182,212,243,275,304,334,365,377};
> 	int i,j,k,p,year,s,weekth,leap=0,q,date;
> 
> 	for(i=0;i<26;i++)//确定第i个400年内的总天数
> 		fh[i]=i*146100;
> 	for(i=0;i<5;i++)
> 		hh[i]=i*36525;//确定第i个世纪内的总天数
> 
> 
> 	cin>>days;
> 	while(days!=-1)
> 	{
> 		days++;
> 		for(i=0;i<26;i++)//确定days在第几个400年内,若days<fh[i+1],则days在第i个400年内
> 			if(days<=fh[i+1])
> 				break;
> 	
> 		days=days-fh[i];
> 		for(j=0;j<5;j++)//确定days在第几个世纪内,若days<hh[j+1],则days在第j个世纪内
> 			if(days<=hh[j+1])
> 				break;
> 		
> 		days=days-hh[j];
> 		for(k=0;k<27;k++)//确定days在第几个4年内,若days<1461*(k+1),则says在第k个四年内
> 			if(days<=1461*(k+1))
> 				break;
> 
> 		days=days-1461*k;
> 		for(p=0;p<6;p++)//确定days在第几年内,若days<y[p+1],则days在dip个年内
> 			if(days<=y[p+1])
> 				break;
> 
> 		days=days-y[p];//days在本年的第几天.
> 		year=2000+i*400+j*100+k*4+p;//year就是本年份的年值
> 		if(year%4==0&&year%100!=0||year%4==0&&year%100==0)
> 			leap=1;
> 		if(leap)//确定是第几个月
> 			for(q=0;q<15;q++)
> 			{
> 				if(days<=dleap[q+1])
> 				{
> 					date=days-dleap[q];
> 					break;
> 				}
> 			}
> 
> 		else
> 			for(q=0;q<15;q++)
> 			{
> 				if(days<=dfl[q+1])
> 				{
> 					date=days-dfl[q];
> 					break;
> 				}
> 			}
> 
> 		q++;//月份
> 		s=year-1+(year-1)/4-(year-1)/100+(year-1)/400+days;
> 		weekth=s%7;//weekth就是星期数
> 		
> 		//printf("%d-%d-%d %s\n",year,q,date,week[weekth]);
> 		cout<<year<<'-'<<setfill('0')<<setw(2)<<q<<'-'<<setfill('0')<<setw(2)<<date<<' '<<week[weekth]<<endl;
> 		cin>>days;
> 	}
> 
> 	return 1;
> }