| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
Re:牛牛们,帮我看一下,确实wa的不知道怎么弄了...In Reply To:牛牛们,帮我看一下,确实wa的不知道怎么弄了... Posted by:yujiashan at 2006-12-22 21:25:52 > 基本思路是:
> 分别判断矩形的四条边是否与线段相交。
> (两线段重叠不算相交)
重叠算相交也试了,一样wa
> 谢谢了!
> #include<stdio.h>
> double xs,ys,xe,ye,a,b,c,d;
> void solve()
> {
> double temp,xl=(a<c)?a:c,xr=(a>c)?a:c,yt=(b>d)?b:d,yb=(b<d)?b:d,xi=(xs<xe)?xs:xe,xa=(xs>xe)?xs:xe,yi=(ys<ye)?ys:ye,ya=(ys>ye)?ys:ye;
> if (xe==xs)
> {
> if (xe==xl||xe==xr)
> {
> if (yi==yt)
> {
> printf("T\n");
> return;
> }
> if (ya==yb)
> {
> printf("T\n");
> return;
> }
> printf("F\n");
> return;
> }
> if (xe>xl&&xe<xr)
> {
> if (yi>yt)
> {
> printf("F\n");
> return;
> }
> if (ya<yb)
> {
> printf("F\n");
> return;
> }
> if (yi>yb&&ya<yt)
> {
> printf("F\n");
> return;
> }
> printf("T\n");
> return;
> }
> printf("F\n");
> return;
> }
> if (ye==ys)
> {
> if (ye==yb||ye==yt)
> {
> if (xi==xr)
> {
> printf("T\n");
> return;
> }
> if (xa==xl)
> {
> printf("T\n");
> return;
> }
> printf("F\n");
> return;
> }
> if (ye>yb&&ye<yt)
> {
> if (xi>xr)
> {
> printf("F\n");
> return;
> }
> if (xa<xl)
> {
> printf("F\n");
> return;
> }
> if (xi>xl&&xa<xr)
> {
> printf("F\n");
> return;
> }
> printf("T\n");
> return;
> }
> printf("F\n");
> return;
> }
> temp=((xe-xs)*(yt-ye))/(ye-ys)+xe;
> if (temp>=xl&&temp<=xr&&temp>=xi&&temp<=xa)
> {
> printf("T\n");
> return;
> }
> temp=((xe-xs)*(yb-ye))/(ye-ys)+xe;
> if (temp>=xl&&temp<=xr&&temp>=xi&&temp<=xa)
> {
> printf("T\n");
> return;
> }
> temp=(ye-ys)*(xl-xe)/(xe-xs)+ye;
> if (temp>=yb&&temp<=yt&&temp>=yi&&temp<=ya)
> {
> printf("T\n");
> return;
> }
> temp=(ye-ys)*(xr-xe)/(xe-xs)+ye;
> if (temp>=yb&&temp<=yt&&temp>=yi&&temp<=ya)
> {
> printf("T\n");
> return;
> }
> printf("F\n");
> }
> int main()
> {
> int n;
> scanf("%d",&n);
> while (n--)
> {
> scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&xs,&ys,&xe,&ye,&a,&b,&c,&d);
> solve();
> }
> return 0;
> }
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator