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你只要记录所有数的和以及最大的那n1个和最小的那n2个数就可以了,最后用总和减掉它们,再求平均就okIn Reply To:这个题目就是数据存储,太大。究竟怎么搞这类问题,大牛请教了。(内涵我的错误代码〉 Posted by:drownever at 2006-12-21 20:43:44 > #include<iostream.h>
> #include<stdio.h>
> int main()
> {
> long nl,ng,n;
> long array[5000000];
> scanf("%d %d %d",ng,nl,n);
> for(int v=0;v<n;v++)
> scanf("%d",&array[v]);
> while(nl!=0&&ng!=0&&n!=0)
> {
> for(int i=0;i<n;i++)
> for(int j=i;j<n;j++)
> {
> if(array[i]>array[j])
> {
> long temp=array[i];
> array[i]=array[j];
> array[j]=temp;
> }
> }
> long sum=0; //init and updata ,continue,,,,,
> for(int e=nl;e<n-ng;e++)
> sum=sum+array[e];
> sum=sum/(n-ng-nl);
> //output result.
> printf("%0.6f\n",sum);
> //get new data for input .
> scanf("%d %d %d",ng,nl,n);
> for(int b=0;b<n;b++)
> scanf("%d",&array[b]);
> }
> return 0;
> }
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