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你只要记录所有数的和以及最大的那n1个和最小的那n2个数就可以了,最后用总和减掉它们,再求平均就ok

Posted by achilles at 2006-12-21 20:48:58 on Problem 2833
In Reply To:这个题目就是数据存储,太大。究竟怎么搞这类问题,大牛请教了。(内涵我的错误代码〉 Posted by:drownever at 2006-12-21 20:43:44
> #include<iostream.h>
> #include<stdio.h>
> int main()
> {
> 	long nl,ng,n;
> 	long array[5000000];
> 	scanf("%d %d %d",ng,nl,n);
> 	for(int v=0;v<n;v++)
> 		scanf("%d",&array[v]);
> 	while(nl!=0&&ng!=0&&n!=0)
> 	{
> 		for(int i=0;i<n;i++)
> 			for(int j=i;j<n;j++)
> 			{
> 				if(array[i]>array[j])
> 				{
> 					long temp=array[i];
> 					array[i]=array[j];
> 					array[j]=temp;
> 				}
> 			}
>         long sum=0;   //init and updata ,continue,,,,,
> 		for(int e=nl;e<n-ng;e++)
> 			sum=sum+array[e];
> 		sum=sum/(n-ng-nl);
> 		//output result.
> 	    printf("%0.6f\n",sum); 
> 		//get new data for input .
> 		scanf("%d %d %d",ng,nl,n);
> 	    for(int b=0;b<n;b++)
> 	    	scanf("%d",&array[b]);
> 	}
> 	return 0;
> }

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