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opt[i][j] = max{ opt[k][j-1], 住在第request[k+1]到第request[i]层的人中最迟到达时间 }

Posted by Bluebird at 2006-11-17 20:52:53 on Problem 1771
In Reply To:同问,WA中 Posted by:Bluebird at 2006-11-17 20:50:35


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