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Re:Floyd算法空间复杂度是O(n*n*n)的, 您怎么算的?

Posted by guoxi022 at 2006-11-17 10:45:45
In Reply To:Floyd算法空间复杂度是O(n*n*n)的, 您怎么算的? Posted by:sunmoonstar at 2006-11-17 10:41:44 
Floyd算法需要用到一个存储中间结点的矩阵，这个矩阵是三维的，如果有n个node，那么Floyd算法最多要占用n*n*n的空间，不知道对不对？
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