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不知道可不可以简化成这样搜

Posted by PC0400322032 at 2004-08-13 17:19:59 on Problem 1348
#include <stdio.h>
int v[5],a[6];
bool dfs(int k,int m)
{
	if(k==4)
	{
		if(m==a[4])
			return 1;
		else
			return 0;
	}
	for(int i=0;i<4;i++)
		if(v[i]==0)
		{
			v[i] = 1;
			if(dfs(k+1,m*a[i]))
				return 1;
			if(dfs(k+1,m+a[i]))
				return 1;
			if(dfs(k+1,m-a[i]))
				return 1;
			if(a[i]!=0)
			{
				if(dfs(k+1,m/a[i]))
					return 1;
			}
			v[i] = 0;
		}
	return 0;
}
bool done()
{
	for(int i=0;i<4;i++)
	{
		v[i] = 1;
		if(dfs(1,a[i]))
			return 1;
	}
	return 0;
}
void main()
{
	int i;
	while(1)
	{
		scanf("%d",&a[0]);
			if(a[0]<0)
				break;
		v[0] = 0;
		for(i=1;i<5;i++)
		{
			scanf("%d",&a[i]);
			v[i] = 0;
		}
		for(i=0;i<5;i++)
			printf("%d ",a[i]);
		if(done())
			printf("OK!\n");
		else
			printf("NO!\n");
	}
}

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