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church men 多的时候也可以吧，同样用 wild 开船，运church，然后运wild，交替，任何一边都不会有danger的情况，正好2*（m+n)-3就运完了，哭了In Reply To:貌似你们的策略应该是在两种人人数相等的时候是正确的，但church man多于wild man的时候似乎最优策略并不确定，还是搜出来比较好～～～ Posted by:liulibo133 at 2006-11-10 14:43:50 Followed by:
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