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按照题目给出的公式,然后根据n的奇偶性,M^n=(M^(n/2))^2或者M^n=(M^(n/2))^2*M递归

Posted by cheapwine at 2006-11-02 23:40:29 on Problem 3070
In Reply To:怎么做? Posted by:Csea at 2006-11-02 21:48:10


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