是不是命令后的空格也要输出
所以"RESULT:"后至少有2个空格


#include<stdio.h>
#include<string.h>
int main()
{
	char commad[100],arry[10005],pre,tmp,clj[26];
	int i,size,brry[26],key,flag;
	for(i=0;i<26;i++)
	{
		clj[i]=i+'A';//值对应的字母
		brry[i]=i;//字母对应的值
	}
	while(scanf("%s",commad)!=EOF)
	{
		gets(arry);
		size=strlen(arry);pre='A';
		if(strcmp(commad,"ENCRYPT")==0)
		{
			for(i=0;i<size;i++)
			{
				if(arry[i]>='a'&&arry[i]<='z')
				{
					tmp=arry[i];
					arry[i]=clj[(brry[arry[i]-'a']-brry[pre-'A']+26)%26];
					pre=tmp-32;
					if(arry[i]>='A'&&arry[i]<='Z')
						arry[i]+=32;
				}
				else if(arry[i]>='A'&&arry[i]<='Z')
				{
					
					tmp=arry[i];
					arry[i]=clj[(brry[arry[i]-'A']-brry[pre-'A']+26)%26];
					pre=tmp;
					if(arry[i]>='a'&&arry[i]<='z')
						arry[i]-=32;
				}
				else pre='A';
			}
			printf("RESULT: %s\n",arry);
		}
		else if(strcmp(commad,"DECRYPT")==0)
		{
			for(i=0;i<size;i++)
			{
				if(arry[i]>='a'&&arry[i]<='z')
				{
					arry[i]=clj[(brry[pre-'A']+brry[arry[i]-'a'])%26];
					pre=arry[i];
					if(arry[i]>='A'&&arry[i]<='Z')
						arry[i]+=32;
				}
				else if(arry[i]>='A'&&arry[i]<='Z')
				{
					
					arry[i]=clj[(brry[pre-'A']+brry[arry[i]-'A'])%26];
					pre=arry[i];
					if(arry[i]>='a'&&arry[i]<='z')
						arry[i]-=32;
				}
				else pre='A';
			}
			printf("RESULT: %s\n",arry);
		}
		else if(strcmp(commad,"CIPHER")==0)
		{
			for(i=0;i<26;i++)
				brry[i]=26;
			key=0;flag=1;
			for(i=0;i<size;i++)
			{
				if(arry[i]>='a'&&arry[i]<='z')
				{
					clj[key++]=arry[i]-32;
					if(brry[arry[i]-'a']!=26)
					{
						flag=0;
						break;
					}
					else brry[arry[i]-'a']=key-1;
				}
				else if(arry[i]>='A'&&arry[i]<='Z')
				{					
					clj[key++]=arry[i];
					if(brry[arry[i]-'A']!=26)
					{
						flag=0;
						break;
					}
					else brry[arry[i]-'A']=key-1;
				}
				if(flag==0)
					break;
			}
			if(key!=26)
				flag=0;
			if(flag==0)
			{
				for(i=0;i<26;i++)
				{
					clj[i]=i+'A';
					brry[i]=i;
				}
				printf("Bad cipher.  Using default.\n");
			}
			else 
			{
				printf("Good cipher.  Using ");
				for(i=0;i<26;i++)
					printf("%c",clj[i]);
				printf(".\n");
			}
		}
		else printf("Command not understood.\n");
	}
	return 0;
}

• 大概讲讲你得思路啊,怕是大多数人都没有耐心去看那么长得程序 :) (2578) atlas_of_rruucc 2004-08-08 00:01:51
  • Re:大概讲讲你得思路啊,怕是大多数人都没有耐心去看那么长得程序 :) (77) atlas_of_rruucc 2004-08-08 00:06:32
• 程序主要是三个部分,分别模拟三个commad (507) windbells 2004-08-08 09:27:31
• up (2) windbells 2004-08-10 09:06:25
  • Re:up (112) LIANGLIANG 2004-08-10 18:06:45
• 郁闷 题目没看清 (0) windbells 2004-08-11 18:07:35