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Re:可以bfs，比dijkstra要快。二维数组best[a][b],表示当前在a点方向指向b点的最快到达时间。最后结果就是Min(best[n][i])(0<i<=n)

Posted by bupt003 at 2006-11-01 14:04:09 on Problem 3072
In Reply To:Re:可以bfs，比dijkstra要快。二维数组best[a][b],表示当前在a点方向指向b点的最快到达时间。最后结果就是Min(best[n][i])(0<i<=n) Posted by:Iambitious at 2006-11-01 13:58:49 
我也两种都做了，bfs 15ms，dij 300+。。可能dij方法不同吧
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