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那x^2+1=0不也可以分成(x+sqrt(i))*(x-sqrt(i)),而且根据题目说只要是coefficients是实数不就可以了,那为什么x^2+1=0不能分解In Reply To:在实数域上，奇次一定有一个根，偶次有共轭虚根,总是可以分解成两个n/2的多项式。 Posted by:yangguo981 at 2006-05-16 22:28:26 Followed by:
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