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一时间看不明白!In Reply To:knuth的源代码 Posted by:xemoaya at 2005-09-23 12:40:01 > knuth打印出了建树的过程,自己给一些数据试验一下应该能找到程序的脉络。这个算法可以用来做最优二叉排序树
> 的建立。这道题只用了前面的combin函数。
> #include <cstdio>
> #include <iostream>
> using namespace std;
>
> const int size = 64000;
> int w[size]; /* node weights */
> int l[size],r[size]; /* left and right children */
> //辅助数组,仅仅为了列印方便
> int d[size]; /* depth */
> int q[size]; /* working region */
> int v[size]; /* number of node in working region */
> //辅助数组,仅仅为了列印方便
> int t; /* current size of working region */
> //标记当前未处理的节点个数
> int m; /* current node */
>
>
> int ans;
> void combine(int t);
> void mark(int k, int p);
> void build(int b);
> int main()
> {
> int i, j, k, n;
> for(; ;)
> {
> scanf("%d", &n);
> if(!n) break;
> --n;
>
> for(j = 0; j <= n; j++)
> {
> scanf("%d", &w[j]);
> l[j] = r[j] = -1;
> }
> if(!n)
> {
> printf("0\n");
> continue;
> }
> m=n;
> t=1;
> ans = 0;
> q[0]=1000000000; /* infinity */
> q[1]=w[0]; v[1]=0;
> for(k=1;k<=n;k++)
> {
> while(q[t-1] <= w[k]) //从左往右扫描,第一次遇到a, b, c且a > b, c > a,则将a, b合并
> combine(t);
> t++;
> q[t]=w[k];
> v[t]=k;
> for (j=1;j<=t;j++) printf("%d ",q[j]); printf("\n");
> }
> while(t > 1)
> combine(t);
> cout << ans << endl;
> /* mark(v[1],0);
> t=0; m=2*n;
> build(1);*/
> }
> }
>
> void combine(int k)
> {
> int j,d,x;
> m++; l[m]=v[k-1]; r[m]=v[k]; w[m]=x=q[k-1]+q[k];//注意合并成为一棵树,新节点放在w数组的后面
> printf(" node %d(%d)=%d(%d)+%d(%d)\n",m,x,l[m],w[l[m]],r[m],w[r[m]]);//原程序中的列印
> ans += x;
> t--;
> for (j=k;j<=t;j++) q[j]=q[j+1],v[j]=v[j+1];
> for (j=k-2;q[j]<x;j--) q[j+1]=q[j],v[j+1]=v[j];
> q[j+1]=x; v[j+1]=m;
> for (d=1;d<=t;d++) printf("%d ",q[d]);
> printf("\n");
> while (j>0 && q[j-1]<=x) {
> d=t-j; combine(j); j=t-d;
> }
> }
>
>
> void mark(int k, int p)//int k; /* node */int p; /* starting depth */
> {
> //printf(" node %d(%d) has depth %d\n",k,w[k],p);
> d[k]=p;
> if (l[k]>=0) mark(l[k],p+1);
> if (r[k]>=0) mark(r[k],p+1);
> }
>
>
>
> /*
> @ The |build| subroutine rebuilds a tree from the depth table,
> by doing a depth-first search according a slick idea by Bob Tarjan.
> It creates a tree rooted at node~|m| having leftmost leaf~|t|.
>
> @<Sub...@>=*/
> void build(int b)
> {
> int j=m;
> if (d[t]==b) l[j]=t++;
> else {
> m--; l[j]=m; build(b+1);
> }
> if (d[t]==b) r[j]=t++;
> else {
> m--; r[j]=m; build(b+1);
> }
> // printf(" node %d = %d + %d\n", j,l[j],r[j]);
> }
>
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