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是这个样子的，把一个操作变成四个操作，查询的时候只要计算总共对这个点进行了多少次操作就可以了In Reply To:那要把一个矩形内的元素全部置反怎么操作？求一个元素是否还需要求四个矩形然后利用容斥原理去计算，实在想不到好办法？ Posted by:nuanran at 2006-10-06 20:58:42 Followed by:
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