#include<iostream>
using namespace std;
int main()
{
    int p,e,i,d,x,n;
    cin>>p>>e>>i>>d;
    x=i;n=1;
    while(p!=-1&&e!=-1&&i!=-1&&d!=-1)
    {                         
      while(!((x-p)%23==0&&(x-e)%28==0))
        x+=33;
        if(x!=0)
        cout<<"Case "<<n<<": the next triple peak occurs in "<<x-d<<" days."<<endl;
       else
        cout<<"Case "<<n<<": the next triple peak occurs in "<<21252-d<<" days."<<endl;
       n++;
        cin>>p>>e>>i>>d; 
        x=i;
      }   
   return 0;
}    

• If a triple peak occurs on the given date, you should give the number of days to the next occurrence of a triple peak. (0) foranswer 2006-09-27 20:46:50