> #include<iostream>
> #include<cstdio>
> #include<string>
> #include<iomanip>
> #include<cmath>
> using namespace std;
> int main(int argc, char* argv[])
> {
> 	char a[40], b[40];
----------------------------------
> 	int n;
> 	cin>>n;
> 	cin.ignore();
> 	for(int j = 1; j <= n; ++ j){
> 		gets(a);
> 		gets(b);
> 		int num1[26] = {0}, num2[26] = {0};
> 		int len1 = strlen(a);
> 		int len2 = strlen(b);
> 		int i, sum = 0;
> 		for(i = 0; i < len1; ++ i) num1[ a[i] - 'a'] ++;
> 		for(i = 0; i < len2; ++ i) num2[ b[i] - 'a'] ++;
> 		for(i = 0; i < 26; ++ i) sum += (int)abs(num1[i] - num2[i]);
> 		cout<<"Case #"<<j<<":  "<<sum<<endl;
> 	}
> 	return 0;
> }
数组开少了
这是我改完后的程序
#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int main()
{
	char a[200],b[200];
	int n,i,j,sum,num2[26],num1[26];
	scanf("%d",&n);scanf("\n");
	for(j=1;j<=n;j++)
	{
		gets(a);
		gets(b);
		memset(num1,0,sizeof(num1));
		memset(num2,0,sizeof(num2));
		sum=0;
		for(i=0;i<strlen(a);i++) 
			num1[a[i]-'a']++;
		for(i=0;i<strlen(b);i++) 
			num2[b[i]-'a']++;
		for(i=0;i<26;i++) 
			sum+=(int)abs(num1[i]-num2[i]);
		printf("Case #%d:  %d\n",j,sum);
	}
	return 0;
}

• Re:问题在这 (665) KosonLau 2006-12-22 01:08:41