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老是WA,牛人解惑!!#include <iostream> using namespace std; int a[100][3]; int b[100][100]; int N,M,k; int Minmoney(int disN,int disM,int ttN,int ttM);//用来求到达(disN,disM)需要最少money int main() { cin>>N>>M>>k; int minN,minM; while(N||M||k) {minN=100; minM=100; for(int i=0;i<k;i++) {cin>>a[i][0]>>a[i][1]>>a[i][2]; if(a[i][0]<minN) minN=a[i][0]; if(a[i][1]<minM) minM=a[i][1]; } b[N][M]=20000; for(i=0;i<=N;i++) for(int t=0;t<=M;t++) b[i][t]=Minmoney(i,t,minN,minM);//求到达(i,t)点所需要最少money if(b[N][M]<20000) cout<<b[N][M]<<endl; else cout<<-1<<endl; cin>>N>>M>>k; } return 0;} int Minmoney(int disN,int disM,int ttN,int ttM) {int j; int tmp; int min=20000; if(disN==0&&disM==0) return 0; if((disN<ttN&&disN!=0)||(disM!=0&&disM<ttM)) return 20000; else {for(j=0;j<k;j++) {if(a[j][0]>disN||a[j][1]>disM) continue; tmp=b[disN-a[j][0]][disM-a[j][1]]+a[j][2]; if(tmp<min) min=tmp; } return min; } } Followed by:
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