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Re:是a(n+1)+n*a0....吧

Posted by lxp_rs at 2006-08-25 00:12:58 on Problem 2601
In Reply To:Re:公式也不难吧 Posted by:fly_away at 2006-08-17 23:52:54
> 公式是这样的:a(1) = (a(n+1) - n * a0 - 2 * ((c1 + c2 + ...+ cn) +  (c1 + c2 + ... + cn-1) + ... + (c1 + c2) + c1) / (n + 1)
> ^_^

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