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改过的AC精简版(C++)In Reply To:这里边的所有测试数据都通过了,还是WA,哪位看下哪错了,给些测试数据! Posted by:194 at 2006-08-20 14:18:14 #include <cstdio> #include <algorithm> using namespace std; char a[1010],c; sm(){int i,sum=0;for(i=0;a[i];i++)sum+=a[i]-'0';return sum;} pt(){ int j,t; t=sm(); if(t%3==0){ if(t){for(j=strlen(a)-1;~j;j--)printf("%c",a[j]);puts("");} else puts("0"); return 1; }else return 0; } void pe(){puts("impossible");} int main(){ int i,j,k,m,sum,len; scanf("%s",a);len=strlen(a);sort(a,a+len); if(a[0]=='0'){ if(pt())return 0; for(i=1,sum=sm()%3;a[i]&&(a[i]-'0')%3!=sum;i++); if(!a[i]){ for(;;){ for(m=1;(a[m]-'0')%3==0;m++); for(j=m;a[j];j++)a[j]=a[j+1]; if(pt())return 0; } } for(j=i;j<len;j++)a[j]=a[j+1]; pt();return 1; }else{ for(i=0;a[i]&&a[i]!='5';i++); if(!a[i]){pe();return 0;} c=a[i];a[i]=a[0];a[0]=c; sort(a+1,a+len); if(pt())return 0; for(i=1,sum=sm()%3;a[i]&&(a[i]-'0')%3!=sum;i++); if(!a[i]){ for(m=1,k=0;a[m]&&((a[m]-'0')%3==0||(a[m]-'0')%3==5%3);m++)if((a[m]-'0')%3==5%3)k++; if(k==1){pe();return 1;} while(1){ for(m=1;a[m]&&(a[m]-'0')%3==0;m++); if(!a[m]){pe();return 0;} for(j=m;a[j];j++)a[j]=a[j+1]; if(pt())return 1; } } for(j=i;j<strlen(a);j++)a[j]=a[j+1]; pt();return 1; } } Followed by:
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