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Passing by reference or by parameter in lazy evalutation?Sonsider such two functions: f(x) = x + 1 g(x) = f(x) + x + 1 Consider lazy evaluation. If I call g(2+2), it first calls f(2+2), where 2+2 is evaluated. Is that value (2+2=4) returned back to g, so it doesn't evaluate x again, when it needs it in the rest of the function (" + x + 1")? Followed by: Post your reply here: |
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