Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
发个证明,嘿嘿。Proof: Suppose a is the string. if a[n]=0; then a[n]=a[n-1]; if a[n]=1; then a[n-1] must be 0; so a[n]=a[n-2]; 'Cause a[n]=0 or a[n]=1; so a[n]=a[n-1]+a[n-2]; Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator