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Re:请教只排一次序的算法,我排了两次,1xxxMSIn Reply To:Re:请教只排一次序的算法,我排了两次,1xxxMS Posted by:Huacm56 at 2006-07-27 12:34:27 > 不用排序的算法
> #include<stdio.h>
> int re[10010]={0};
> int main()
> { int N,D,C,i,j,sum,max,right=0,result;
> while(scanf("%d",&N)&&N)
> { for(i=0;i<10010;i++)
> re[i]=10010;
> sum=0;result=1;
> for(i=0;i<N;i++)
> { scanf("%d%d",&D,&C);
> if(re[D]>C) re[D]=C;
> if(right<D) right=D;
> }
> i=0;
> while(re[i]==10010) i++;
> max=re[i];
> for(j=i+1;j<=right;j++)
> if(re[j]<max)
> {result++;max=re[j];}
> printf("%d\n",result);
> }
> return 0;
> }
46MS
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