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Re:谁能给一组测试数据,实在wa的不行了In Reply To:谁能给一组测试数据,实在wa的不行了 Posted by:6233843 at 2006-07-25 12:33:36 #include <string> #include <algorithm> #include <iostream> using namespace std; //#include <fstream> //using namespace std; //ifstream cin("t.in"); //ofstream cout("t.out"); char data[16][90]; char no[10],b[4],temp[2]; int main() { scanf("%s",data[0]); while (1 ) { if (strcmp(data[0],"-1") == 0) return 0; int i; for ( i=0;i<15;i++) { memset(no,0,sizeof(no)); for (int j=0;data[i][j] != 0;j++) { no[data[i][j]-'0']++; //算出了一个串中所有数字的个数 } for (int k=0;k<10;k++) //把新算得串加入下一个串中 { if (no[k] != 0 && no[k] < 10) { temp [0] = no[k] + '0'; temp [1] = k + '0'; strcat(data[i+1],temp); memset(temp,0,sizeof(temp)); } else if (no[k] >=10) //如果某位的个数超过10 就要单独处理 { int p,m= no[k]; for (p=1;m != 0;p--) { b[p] = m%10 + '0'; m = m /10; } b[2] = k+'0'; b[4] = '\0'; strcat (data[i+1],b); memset(b,0,sizeof(b)); } } } int flag = 0; int stop = 0; for (i=0;i<15;i++) { int min; if (strcmp(data[i],data[i+1]) == 0 ) { if ( i == 0 ) { printf("%s is self-inventorying\n",data[0]); stop =1; break; } else { printf("%s is self-inventorying after %d steps\n",data[0],i); stop=1; break; } } else { for (int k=i+2;k+i<=15;k++) { if (strcmp(data[i],data[k]) == 0 ) { if (flag == 0) //如果flag为0 则记录下k-i的值 { min = k-i; flag =1; } else //如果flag为1 则要比较min与k-i的值 并且找出最小的来 { if (min > k-i) { min = k-i; } } } } } if (flag) //如果flag为1 则说明有环的情况 { printf("%s enters an inventory loop of length %d\n",data[0],min); stop =1; break; } } if (stop == 0) printf("%s can not be classified after 15 iterations\n",data[0]); //如果stop为0 说明没有求出正确的解 输出没有解 memset(data,0,sizeof(data)); //给data清0 scanf("%s",data[0]); //重新读入下一组值 } } 大家看看是不是因为我的char数据没有处理好?? Followed by:
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