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Re:谁能给一组测试数据,实在wa的不行了In Reply To:谁能给一组测试数据,实在wa的不行了 Posted by:6233843 at 2006-07-25 12:33:36 #include <string>
#include <algorithm>
#include <iostream>
using namespace std;
//#include <fstream>
//using namespace std;
//ifstream cin("t.in");
//ofstream cout("t.out");
char data[16][90];
char no[10],b[4],temp[2];
int main()
{
scanf("%s",data[0]);
while (1 )
{
if (strcmp(data[0],"-1") == 0) return 0;
int i;
for ( i=0;i<15;i++)
{
memset(no,0,sizeof(no));
for (int j=0;data[i][j] != 0;j++)
{
no[data[i][j]-'0']++; //算出了一个串中所有数字的个数
}
for (int k=0;k<10;k++) //把新算得串加入下一个串中
{
if (no[k] != 0 && no[k] < 10)
{
temp [0] = no[k] + '0';
temp [1] = k + '0';
strcat(data[i+1],temp);
memset(temp,0,sizeof(temp));
}
else if (no[k] >=10) //如果某位的个数超过10 就要单独处理
{
int p,m= no[k];
for (p=1;m != 0;p--)
{
b[p] = m%10 + '0';
m = m /10;
}
b[2] = k+'0';
b[4] = '\0';
strcat (data[i+1],b);
memset(b,0,sizeof(b));
}
}
}
int flag = 0;
int stop = 0;
for (i=0;i<15;i++)
{
int min;
if (strcmp(data[i],data[i+1]) == 0 )
{
if ( i == 0 )
{
printf("%s is self-inventorying\n",data[0]);
stop =1;
break;
}
else
{
printf("%s is self-inventorying after %d steps\n",data[0],i);
stop=1;
break;
}
}
else
{
for (int k=i+2;k+i<=15;k++)
{
if (strcmp(data[i],data[k]) == 0 )
{
if (flag == 0) //如果flag为0 则记录下k-i的值
{
min = k-i;
flag =1;
}
else //如果flag为1 则要比较min与k-i的值 并且找出最小的来
{
if (min > k-i)
{
min = k-i;
}
}
}
}
}
if (flag) //如果flag为1 则说明有环的情况
{
printf("%s enters an inventory loop of length %d\n",data[0],min);
stop =1;
break;
}
}
if (stop == 0)
printf("%s can not be classified after 15 iterations\n",data[0]); //如果stop为0 说明没有求出正确的解 输出没有解
memset(data,0,sizeof(data)); //给data清0
scanf("%s",data[0]); //重新读入下一组值
}
}
大家看看是不是因为我的char数据没有处理好??
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