#include "iostream"
#include "cmath"
using namespace std;
#define ABS(a) ((a)>=0?(a):-(a))
int main()
{
int x,y,m,n,L;
cin>>x>>y>>m>>n>>L;
int steps=0;
if(x==y||((x-y+L)%L)%ABS(m-n))
{
cout<<"Impossible";
}
else
{
do {
++steps;
} while((x+=m)%L!=(y+=n)%L);
cout<<steps<<endl;
}
return 0;
}
怎样的算法？
这哪错啊

• Re:青蛙的约会 怎么算啊 (378) 0906401017 2010-05-03 15:56:53