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到底这里的输出格式是怎样的?#include<iostream.h> void print(int *A,int num) { for(int i=0;i<num;i++) if(A[i]!=0) { if(i==0) cout<<A[i]; else if(A[i]!=A[i-1]) cout<<A[i]; } } int main() { char A[4]={'B','F','P','V'},B[8]={'C', 'G', 'J', 'K', 'Q', 'S', 'X', 'Z'},C[2]={'D','T'},D[1]={'L'},E[2]={'M','N'},F[1]={'R'}; int m; char *temp1=new char[20]; int *temp=new int[20]; while(true) { for(int i=0;i<20;i++) { temp1[i]='\0'; temp[i]=0; } cin>>temp1; for(int j=0;j<20;j++) { if(temp1[j]!='\0') { for(m=0;m<4;m++){ if(A[m]==temp1[j]) temp[j]=1; } for(m=0;m<8;m++) { if(B[m]==temp1[j]) temp[j]=2; } for(m=0;m<2;m++) { if(C[m]==temp1[j]) temp[j]=3; } for(m=0;m<1;m++) { if(D[m]==temp1[j]) temp[j]=4; } for(m=0;m<2;m++) { if(E[m]==temp1[j]) temp[j]=5; } for(m=0;m<1;m++) { if(F[m]==temp1[j]) temp[j]=6; } } } print(temp,20); // for(i=0;i<20;i++) // cout<<temp[i]; cout<<endl; } return 0; } Followed by: Post your reply here: |
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