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基数排序In Reply To:先排序 Posted by:gemenhao at 2006-06-07 11:03:52 > 然后 > 对于数组a[n]中的第i个数 > 前面有 i - 1处于被减, 后面有 n - i为减数(忘了是不是) > a[i]对于总和的贡献就是 > sum += (__int64)cow[i] * (2*i - 1 - n ); > > 结果再乘2 > 时间复杂度为排序 n*(lgn) > 不知是否有 o(n)算法? Followed by: Post your reply here: |
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