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Re:偶的解法:)In Reply To:偶的解法:) Posted by:devilphoenix at 2006-05-23 18:00:20 > 先把light,heavy设为全集,每次得到light'和heavy'进行以下操作 > light=light交light',light=light-heavy > heavy=heavy交heavy,heavy=heavy-light > 最后在light和heavy里面找只剩下一个元素的那个集合,然后把这个元素打印出来就ok even的就是。。 light=light-even right=right-even Followed by: Post your reply here: |
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